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What is the total spin value in case of $_{26} {Fe}^{3 +}$ ion?

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detailed solution

Correct option is C

The electronic configration of $_{26} {Fe}^{3 +}$ ion is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5}$ .

The five electrons in the third shell will all be left unpaired since each orbital in the d subshell should be solely occupied before being linked.

hence, the total spin of $_{26} {Fe}^{3 +}$

$= \pm \frac{1}{2} \times 5 = \pm 2.5$

Thus the option C is correct.

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What is the total spin value in case of 26Fe3+ ion?