When an ideal gas is suddenly allowed to expand adiabatically into an evacuated container, than

When an ideal gas is suddenly allowed to expand adiabatically into an evacuated container, than

A
$Δ S = 0$
B
$Δ G = 0$
C
$Δ U = 0$
D
$Δ p = 0$

Solution:

Adiabatically implies $q = 0$ .

Expansion against vacuum implies, $w = 0$ .

Hence $Δ U = q + w = 0$ .

Thus the option C is correct.

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