Which of the following has maximum number of lone pairs associated with Xe?

We have 

${\mathrm{XeO}}_3:$valence electrons $=8+3\times 6=26$     long pair of electrons around $\mathrm{Xe}=\frac{1}{2}(26-3\times 8)=1$

${\mathrm{XeF}}_4:$valence electrons  $8+4\times 7=36$           long pair of electrons around $\mathrm{Xe}=\frac{1}{2}(36-4\times 8)=3$

${\mathrm{XeF}}_6:$ valence electrons $=8+6\times 7=50$   long pair of electrons around $\mathrm{Xe}=\frac{1}{2}(50-6\times 8)=1$

${\mathrm{XeF}}_2\text{ : }$valence electrons $=8+2\times 7=22$  long pair of electrons around 

$\mathrm{Xe}=\frac{1}{2}(22-2\times 8)=3$