Which of the following is an impossible set of quantum number?

1. A

$n=3,l=2,m=0,s=+\frac{1}{2}$

2. B

$n=3,l=2,m=-2,s=+\frac{1}{2}$

3. C

$n=3,l=2,m=-3,s=-\frac{1}{2}$

4. D

$n=3,l=2,m=-1,s=-\frac{1}{2}$

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Solution:

An impossible set of quantum number is $n=3,l=2,m=-3,s=-\frac{1}{2}$

l can have values ranging from 0 to n-1 for every value of n, while m can have values ranging from 1 to +1 for every value of l.
Consequently, for l=2, m can have values of: 2, 1, 0, 1, and 2, but not 3.

Hence, option C is correct.

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