Which of the following pairs of species has identical value of bond order?

# Which of the following pairs of species has identical value of bond order?

1. A

2. B

$\mathrm{CO}$ and ${\mathrm{N}}_{2}^{+}$

3. C

4. D

${\mathrm{N}}_{2}$ and ${\mathrm{O}}_{2}^{+}$

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### Solution:

Valence electrons of ${\mathrm{N}}_{2}=10$ Electronic Configuration $\left(\sigma 2\mathrm{s}{\right)}^{2}\left(\sigma \ast 2\mathrm{s}{\right)}^{2}{\left(\pi 2{\mathrm{p}}_{x}\right)}^{2}{\left(\pi 2{\mathrm{p}}_{y}\right)}^{2}{\left(\sigma 2{\mathrm{p}}_{z}\right)}^{2}$

Bond order $=\left(8-2\right)/2=3$

Valence electrons of

Bond order $=\left(8-2\right)/2=3$

Valence electrons of $\mathrm{CO}=10$; Same as ${\mathrm{NO}}^{+}$

Valence electrons of ${\mathrm{CN}}^{-}=10;$ Same as ${\mathrm{NO}}^{+}$

Valence electrons of ${\mathrm{N}}_{2}^{-}=11$ Bond order $=\left(9-2\right)/2=3.5$

Valence electrons of ${\mathrm{O}}_{2}^{+}=11$Electronic configuration $\left(\sigma 2\mathrm{s}{\right)}^{2}\left(\sigma \ast 2\mathrm{s}{\right)}^{2}{\left(\sigma 2{\mathrm{p}}_{z}\right)}^{2}{\left(\pi 2{\mathrm{p}}_{x}\right)}^{2}{\left(\pi 2{\mathrm{p}}_{y}\right)}^{2}{\left(\pi \ast 2{\mathrm{p}}_{x}\right)}^{1}$

Bond order $=\left(8-3\right)/2=2.5$