Which of the following set of quantum own correct for an electron in 4f orbital?

The set of quantum own correct for an electron in 4f orbital $n=4,l=3,m=+1,s=+\frac{1}{2}$

The set of quantum numbers for an electron in the 4f orbital is as follows:

The major shell is represented by the principal quantum number n. N = 4 for an electron in the 4f orbital.

The orbitals are represented by the angular momentum quantum number value. which is =+1

The number of electron in S,p,d and f orbitals are 0,1,2 and 3 respectively.

Consequently, l = 3 for an electron in the f orbital.

The range of a magnetic quantum number's possible values ranges from - l to + l.

So, m  = -3, -2, -1, 0, 1, 2, 3.

An electron in a certain orbital will have a spin quantum number of m s = +1/2 or -1/2.
Therefore, ,$\mathrm{n} = 4, \mathrm{l} = 3, \mathrm{m} \mathrm{l} = +1, \mathrm{m} \mathrm{s} = +1/2$ is the right response.