Which of the reactions occurs at anode when electrolysis of ${CuSO}_{4}$ solution is done using platinum electrodes?

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$Cu \to {Cu}^{2 +} + 2 e^{-}$

$2 {SO}_{4}^{2 -} + 2 H_{2} O \to H_{2} {SO}_{4} + O_{2} + 4 e^{-}$

$2 Cu \to {Cu}_{2}^{2 +} + 2 e^{-}$

$2 H_{2} O \to O_{2} + 4 H^{+} + 4 e^{-}$

answer is D.

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Detailed Solution

Water is oxidized in preference to ${SO}_{4}^{2 -}, Cu$ metal is not available as anode is made of platinum.

Electrolysis is the technique of causing a chemical change in a material by passing an electric current through it. The material either loses or gets an electron during the chemical transition (oxidation or reduction).

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