2m white counters and 2n red counters are arranged in a straight line with (m + n) counters on each side of a central mark. The number of ways of arranging the counters, so that the arrangements are symmetrical with respect to the central mark, is

2m white counters and 2n red counters are arranged in a straight line with (m + n) counters on each side of a central mark. The number of ways of arranging the counters, so that the arrangements are symmetrical with respect to the central mark, is

  1. A

    (m+n)!m!n!

  2. B

     2m+2nC2m

  3. C

    12(m+n)!m!n!

  4. D

    none of these

    Register to Get Free Mock Test and Study Material



    +91



    Live ClassesRecorded ClassesTest SeriesSelf Learning

    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    Arrange m white and n red counters on one side of the central mark. This can be done in (m+n)!m!n!

    Chat on WhatsApp Call Infinity Learn

      Talk to our academic expert!



      +91



      Live ClassesRecorded ClassesTest SeriesSelf Learning

      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.