9 a 2 + 4 b 2 + c 2 − 12 a b − 6 a c + 4 b c

(3a−2b−c)2= - Infinity Learn

A
$9 a^{2} - 4 b^{2} - c^{2} - 12 a b - 6 a c + 4 b c$
B
$9 a^{2} + 4 b^{2} - c^{2} - 12 a b - 6 a c - 4 b c$
C
$9 a^{2} + 4 b^{2} + c^{2} - 12 a b - 6 a c + 4 b c$
D
$9 a^{2} + 4 b^{2} + c^{2} + 12 a b + 6 a b - 4 b c$

Solution:

$\begin{array}{l} {(3 a - 2 b - c)}^{2} \\ = {(3 a)}^{2} + {(- 2 b)}^{2} + {(- c)}^{2} + 2 (3 a) (- 2 b) + 2 (- 2 b) (- c) + 2 (3 a) (- c) \\ = 9 a^{2} + 4 b^{2} + c^{2} - 12 a b + 4 b c - 6 a c \end{array}$

${(3 a - 2 b - c)}^{2} =$

Solution:

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