63+2−5= - Infinity Learn

$\frac{6}{3 + \sqrt{2} - \sqrt{5}} \times \frac{3 + \sqrt{2} + \sqrt{5}}{3 + \sqrt{2} + \sqrt{5}}$

$= \frac{6 (3 + \sqrt{2} + \sqrt{5})}{{(3 + \sqrt{2})}^{2} - {(\sqrt{5})}^{2}} = \frac{6 (3 + \sqrt{2} + \sqrt{5})}{9 + 2 + 6 \sqrt{2} - 5}$

$= \frac{6 (3 + \sqrt{2} + \sqrt{5})}{6 + 6 \sqrt{2}} = \frac{6 (3 + \sqrt{2} + \sqrt{5})}{6 (1 + \sqrt{2})}$

$= \frac{3 + \sqrt{2} + \sqrt{5}}{1 + \sqrt{2}} \times \frac{\sqrt{2} - 1}{\sqrt{2} - 1}$

$= \frac{3 \sqrt{2} - 3 + 2 - \sqrt{2} + \sqrt{10} - \sqrt{5}}{1}$

$= 2 \sqrt{2} + \sqrt{10} - \sqrt{5} - 1$

$\frac{6}{3 + \sqrt{2} - \sqrt{5}} =$