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A code word of length 4 consists two distinct consonants in the English alphabet followed by two digits from 1 to 9, with repetition allowed in digits. If the number of code words so formed ending with an even digit is 432 k, then  k is equal to

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a
5
b
49
c
35
d
7

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detailed solution

Correct option is C

.Number of code words ending with even digit

=(21)(20)(9)(4)432k=(21)(20)(9)(4)k=35.

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