A code word of length 4 consists two distinct consonants in the English alphabet followed by two digits from 1 to 9, with repetition allowed in digits. If the number of code words so formed ending with an even digit is 432 k, then  k is equal to

# A code word of length 4 consists two distinct consonants in the English alphabet followed by two digits from 1 to 9, with repetition allowed in digits. If the number of code words so formed ending with an even digit is 432, then  is equal to

1. A

5

2. B

49

3. C

35

4. D

7

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### Solution:

.Number of code words ending with even digit

$\begin{array}{l}=\left(21\right)\left(20\right)\left(9\right)\left(4\right)\\ \therefore 432k=\left(21\right)\left(20\right)\left(9\right)\left(4\right)\\ ⇒k=35.\end{array}$

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