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$\cos^{2} θ + \cos^{2} (θ + α) - 2 \cos α \cos θ \cos (θ + α) =$

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detailed solution

Correct option is D

$\cos^{2} θ + \cos (θ + α) [\cos (θ + α) - 2 \cos α . \cos θ]$

$= \cos^{2} θ + \cos (θ + α) [- \cos θ \cos α - \sin θ \sin α]$

$= \cos^{2} θ - \cos (θ + α) \cos (θ - α)$

$= \cos^{2} θ - (c o s^{2} θ - s i n^{2} α) = s i n^{2} α .$

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cos2θ + cos2 (θ + α) - 2 cosα cosθ cos (θ +α)=