Mathematicsddx1−cosx1+cos2x=

$\frac{d}{d x} (\sqrt{\frac{1 - \cos x}{1 + \cos 2 x}}) =$

A
$- \sec^{2} x$
B
$\cos e c^{2} x$
C
$- \cos e c^{2} x$
D
$\sec^{2} x$

Solution:

$\frac{d}{d x} (\sqrt{\frac{1 - \cos x}{1 + \cos 2 x}})$

$= \frac{d}{d x} (\sqrt{\frac{2 \sin^{2} x}{2 \cos^{2} x}})$

$= \frac{d}{d x} (\tan x)$

$= \sec^{2} x$

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