Search for: ∫dxa2sin2x+b2cos2x is equal to ∫dxa2sin2x+b2cos2x is equal to A1abtan−1atanxb+CBabtan−1atanxb+CCabtan−1atanxb-CDNone of the above Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:∫dxa2sin2x+b2cos2x=∫sec2xdxa2tan2x+b2=1a2∫dtt2+ba2 where, t=tanx=1a2⋅abtan−1tb/a+C=1abtan−1a(tanx)b+CPost navigationPrevious: Let α and β be the roots of equation px2+ qx+ r = 0 p≠0 If p ,q and r, n AP and 1α+1β=4 then the value of |α−β| isNext: The value of ∫dxx+x3 is Related content NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023