∫dxa2sin2⁡x+b2cos2⁡x is equal to 

dxa2sin2x+b2cos2x is equal to 

  1. A

    1abtan1atanxb+C

  2. B

    abtan1atanxb+C

  3. C

    abtan1atanxb-C

  4. D

    None of the above 

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    Solution:

    dxa2sin2x+b2cos2x=sec2xdxa2tan2x+b2=1a2dtt2+ba2

     wheret=tanx=1a2abtan1tb/a+C=1abtan1a(tanx)b+C

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