∫dxsin⁡x−cos⁡x+2 is equal to

dxsinxcosx+2 is equal to

  1. A

    12tanx2+π8+C

  2. B

    12tanx2+π8+C

  3. C

    12cotx2+π8+C

  4. D

    12cotx2+π8+C

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    Solution:

    dxsinxcosx+2=dxsinx22cosx22+2=dx2sinxsinπ4cosxcosπ4+1=12dx1cosx+π4=12dx1cos2x2+π8=12dx2sin2x2+π8=122cosec2x2+π8dx=122cotx2+π812+C=12cotx2+π8+C

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