From figure l∥m, and ‘P’ is transversal, then x+y+z=

# From figure $l\parallel m,$ and $‘\text{P}’$ is transversal, then $x+y+z=$

1. A

$70°$

2. B

${255}^{o}$

3. C

${140}^{o}$

4. D

${35}^{o}$

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### Solution:

$2x°=70°\left(\therefore \text{\hspace{0.17em}\hspace{0.17em}corresponding\hspace{0.17em}angles\hspace{0.17em}are\hspace{0.17em}equal}\right)$

$x°=35°$

$2x+y=180°$$\left(\therefore \text{\hspace{0.17em}\hspace{0.17em}linear\hspace{0.17em}pair}\right)$

$70+y=180°$

$y=110$

$\therefore$ $y=z=110°$ $\left(\therefore \text{\hspace{0.17em}corresponding\hspace{0.17em}angles\hspace{0.17em}are\hspace{0.17em}equal}\right)$

$\therefore$$x+y+z=35°+110°+110°=255°$

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