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Q.

Given,f(x)=0x2sin xcos x2sin xx2012x2cos x2x10' then f(x)dx is equal to 

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a

x33x2sin x+sin 2x+C

b

x33x2sin xcos 2x+C

c

x33x2cos xcos 2x+C

d

None of the above 

answer is D.

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Detailed Solution

We have, 

                   f(x)=0x2sin xcos x2sin xx2012x2cos x2x10f(x)=0sin xx22cos  xx2sin x02x1cos x212x0

[interchanging rows and columns]

f(x)=(1)30x2sin xcos x2sin xx2012x2cos x2x10

[taking (-1) common from each column]

 f(x)=f(x)f(x)=0 f(x)dx=c

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