Search for: Given,f(x)=0x2−sin xcos x−2sin x−x201−2×2−cos x2x−10′ then ∫f(x)dx is equal to Given,f(x)=0x2−sin xcos x−2sin x−x201−2x2−cos x2x−10' then ∫f(x)dx is equal to Ax33−x2sin x+sin 2x+CBx33−x2sin x−cos 2x+CCx33−x2cos x−cos 2x+CDNone of the above Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have, ⇒ f(x)=0x2−sin xcos x−2sin x−x201−2x2−cos x2x−10f(x)=0sin x−x22−cos xx2−sin x02x−1cos x−21−2x0[interchanging rows and columns]⇒f(x)=(−1)30x2−sin xcos x−2sin x−x201−2x2−cos x2x−10[taking (-1) common from each column]⇒ f(x)=−f(x)⇒f(x)=0⇒ ∫f(x)dx=cPost navigationPrevious: The equation of the set of points which are equidistant from the points (1,2,3) and (3,2, – 1) isNext: which of the following pairs of points have a distance 43 ?Related content NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023