If 3−23024yyxx=333y3y1010, then the values of x and y is

3y−2x3y−2x3y3y2y+4x2y+4x=333y3y1010Comparing elements we have3y−2x=32y+4x=10Solving (1) and (2), we get x=32,y=2

If 3−23024yyxx=333y3y1010, then the values of x and y is

3y−2x3y−2x3y3y2y+4x2y+4x=333y3y1010Comparing elements we have3y−2x=32y+4x=10Solving (1) and (2), we get x=32,y=2

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If $[\begin{array}{l} 3 & - 2 \\ 3 & 0 \\ 2 & 4 \end{array}] [\begin{array}{l} y & y \\ x & x \end{array}] = [\begin{array}{l} 3 & 3 \\ 3 y & 3 y \\ 10 & 10 \end{array}]$ , then the values of $x and y$ is

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$x = \frac{4}{3}, y = 1$

$x = 5, y = \frac{4}{3}$

$x = \frac{3}{2}, y = 2$

$x = 4, y = \frac{7}{3}$

answer is B.

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$[\begin{array}{l} 3 y - 2 x & 3 y - 2 x \\ 3 y & 3 y \\ 2 y + 4 x & 2 y + 4 x \end{array}] = [\begin{array}{l} 3 & 3 \\ 3 y & 3 y \\ 10 & 10 \end{array}]$

Comparing elements we have

$3 y - 2 x = 3$

$2 y + 4 x = 10$

Solving (1) and (2), we get $x = \frac{3}{2}, y = 2$

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If 3−23024yyxx=333y3y1010, then the values of x and y is

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If $[\begin{array}{l} 3 & - 2 \\ 3 & 0 \\ 2 & 4 \end{array}] [\begin{array}{l} y & y \\ x & x \end{array}] = [\begin{array}{l} 3 & 3 \\ 3 y & 3 y \\ 10 & 10 \end{array}]$ , then the values of $x and y$ is