If  3Tan4α−10Tan2α+3=0 then principal values of ‘α’ are

If  3Tan4α10Tan2α+3=0 then principal values of ‘α’ are

  1. A

    ±450,±360

  2. B

    ±300,±600

  3. C

    ±750,±360

  4. D

    ±600,±150

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    Solution:

    3tan4α10tan2α+3=0

    3tan4α9tan2αtan2α+3=0

    (3tan2α1)(tan2α3)=0

    tan2α=13=132;tan2α=3=(3)2

    α=±300,±600

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