Search for: MathematicsIf 4sin(xy)−5cos(xy)=45, then dydx=If 4sin(xy)−5cos(xy)=45, then dydx=A−xyB−yxC4sin(xy)−5cos(xy)4cos(xy)+5sin(xy)D4cos(xy)+5sin(xy)4sin(xy)−5cos(xy) Fill Out the Form for Expert Academic Guidance!l Grade ---Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pmPlease indicate your interest Live ClassesBooksTest SeriesSelf LearningLanguage ---EnglishHindiMarathiTamilTeluguMalayalamAre you a Sri Chaitanya student? NoYesVerify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:4cos(xy)[xdydx+y(1)]+5sin(xy)[x.dydx+y(1)]=0[xdydx+y][4cos(xy)+5sin(xy)]=0xdydx=−y⇒dydx=−yxRelated content Area of Square Area of Isosceles Triangle Pythagoras Theorem Triangle Formulae Perimeter of Triangle Formula Area Formulae Volume of Cone Formula Matrices and Determinants_mathematics Critical Points Solved Examples Type of relations_mathematics