MathematicsIf 7cosecθ=8, then cotθsinθ=

If $7cosec θ = 8$ , then $\frac{\cot θ}{\sin θ} =$

A
$\frac{8 \sqrt{15}}{49}$
B
$\frac{7}{\sqrt{15}}$
C
$\frac{\sqrt{15}}{8}$
D
$\frac{7}{8}$

Solution:

$cosec θ = \frac{8}{7}$

$\cot θ = \frac{\sqrt{15}}{7}$

$\sin θ = \frac{7}{8}$

$\frac{\cot θ}{\sin θ} = \frac{\sqrt{15}}{7} \times \frac{8}{7} = \frac{8 \sqrt{15}}{49}$

Related content

Area of Isosceles Triangle

Pythagoras Theorem

Triangle Formulae

Perimeter of Triangle Formula

Volume of Cone Formula

Matrices and Determinants_mathematics

Critical Points Solved Examples

Type of relations_mathematics