A=B⇒2x+13y0y2−5y=x+3y2+20 −6⇒2x+1=x+3⇒x=2y2+2=3y⇒y2−3y+2=0(y−1)(y−2)=0y=1(or)2−−−−−−−(i)y2−5y=−6y2−5y+6=0(y−2)(y−3)=0y=2(or)3−−−−−−−(ii)From (i) and (ii)∴y=2∴(x,y)=(2,2)

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If $A = [\begin{matrix} 2 x + 1 & 3 y \\ 0 & y^{2} - 5 y \end{matrix}]$ and $B = [\begin{matrix} x + 3 & y^{2} + 2 \\ 0 & - 6 \end{matrix}]$ are equal matrices then $(x, y) =___$

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(1,1)

(2,2)

(0,1)

(2,1)

answer is B.

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Detailed Solution

$\begin{array}{l} A = B \\ \Rightarrow [\begin{matrix} 2 x + 1 & 3 y \\ 0 & y^{2} - 5 y \end{matrix}] = [\begin{matrix} x + 3 & y^{2} + 2 \\ 0 & - 6 \end{matrix}] \\ \Rightarrow 2 x + 1 = x + 3 \Rightarrow x = 2 \\ y^{2} + 2 = 3 y \Rightarrow y^{2} - 3 y + 2 = 0 \\ (y - 1) (y - 2) = 0 \\ y = 1 (o r) 2 - - - - - - - (i) \\ y^{2} - 5 y = - 6 \\ y^{2} - 5 y + 6 = 0 \\ (y - 2) (y - 3) = 0 \\ y = 2 (o r) 3 - - - - - - - (ii) \\ From (i) and (ii) \\ ∴ y = 2 \\ ∴ (x, y) = (2, 2) \end{array}$