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 If roots of the equation (a - b)x2 + (c - a)x+(b - c) = 0 are equal, then a, b and c are in 

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a
 AP
b
 HP
c
 GP
d
None of these

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detailed solution

Correct option is A

 Since, roots of the equation 
(ab)x2+(ca)x+(bc)=0
 Discriminant, B24AC=0
     (ca)24(ab)(bc)=0     a2+4b2+c2+2ac4ab4bc=0    (a+c2b)2=0a+c=2b
Hence ,a, b, c ate in AP

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