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If $S i n (\frac{π C o t θ}{4}) = C o s (\frac{π T a n θ}{4})$ and $θ$ is in the first quadrant then $θ$ =-----

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detailed solution

Correct option is C

$\sin (\frac{π \cot θ}{4}) = \cos (\frac{π \tan θ}{4})$

on verification $θ = \frac{π}{4}$ satisfies

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If SinπCotθ4=CosπTanθ4 and θ is in the first quadrant then θ=-----