Search for: If the angles A, B, C of a triangle are in A.P., then acsin2C+casin2A=If the angles A, B, C of a triangle are in A.P., then acsin2C+casin2A=A12B32C1D3 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:A,B,C are in A.P Then⇒B=60∘∴acsin2C+casin2A=sinAsinC⋅2sinCcosC+sinCsinA⋅2sinAcosA=2(sinAcosC+cosAsinC) =2sin(A+C)=2sin120∘=3 Post navigationPrevious: The period of sin πx12+cos πx4+tanπx3,Where x represents the greatest integer less than or equal x is Next: If the sides of a right-angled triangle are in AP, then the sines of the acute angles are Related content JEE Main 2023 Session 2 Registration to begin today JEE Main 2023 Result: Session 1 NEET 2024 JEE Advanced 2023 NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria