Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

 If the equations 2ax23bx+4c=0 and  3x24x+5=0  have a common root, then (a+b)/(b+c) is equal to (a,b,cR)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

2931

b

3431

c

12

d

335

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Since, the second equation has imaginary roots. 
 2a3=3b4=4c5=k a=3k2,b=4k3,c=5k4 a+bb+c=3k2+4k34k3+5k4=3431

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
 If the equations 2ax2−3bx+4c=0 and  3x2−4x+5=0  have a common root, then (a+b)/(b+c) is equal to (a,b,c∈R)