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Q.

If the mean of 4, x, 6, 9, y and 13 is 8, then

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a

x y = 16

b

x + y = 16

c

x - y = 16

d

x + y = 8

answer is A.

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Detailed Solution

Mean

= \frac{4 + x + 6 + 9 + y + 13}{6} = 8

$\to$ $32 + x + y = 48$

$x + y = 16$

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If the mean of 4, x, 6, 9, y and 13 is 8, then