MathematicsIf the mean of 4, x, 6, 9, y and 13 is 8, then

If the mean of 4, x, 6, 9, y and 13 is 8, then

A
$x + y = 16$
B
$x - y = 16$
C
$x y = 16$
D
$x + y = 8$

Solution:

Mean

= \frac{4 + x + 6 + 9 + y + 13}{6} = 8

$\to$ $32 + x + y = 48$

$x + y = 16$

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