If the sides of a triangle are 56cm, 60 cm and 52cm long, then its area is

# If the sides of a triangle are 56cm, 60 cm and 52cm long, then its area is

1. A
$1322\text{\hspace{0.17em}}{\text{cm}}^{2}$
2. B
$1311\text{\hspace{0.17em}}{\text{cm}}^{2}$
3. C
$1344\text{\hspace{0.17em}}{\text{cm}}^{2}$
4. D
$1392\text{\hspace{0.17em}}{\text{cm}}^{2}$

Register to Get Free Mock Test and Study Material

+91

Live ClassesRecorded ClassesTest SeriesSelf Learning

Verify OTP Code (required)

### Solution:

$a$ $=$ 56cm

$b$ $=$ 60 cm

$c=$ 52 cm

$s=\frac{a+b+c}{2}=\frac{56+60+52}{2}=\frac{168}{2}$ $=84$ cm

Area $=\sqrt{s×\left(s-a\right)×\left(s-b\right)×\left(s-c\right)}$

$=\sqrt{84×\left(84-56\right)×\left(84-60\right)×\left(84-52\right)}$

$=\sqrt{84×28×24×32}$

$=\sqrt{12×7×4×7×4×6×16×2}$

$=\sqrt{2×6×7×4×7×4×6×16×2}$

$=2×6×7×4×4$

## Related content

 Distance Formula Perimeter of Rectangle Area of Square Area of Isosceles Triangle Pythagoras Theorem Triangle Formulae Volume of Cylinder Perimeter of Triangle Formula Area Formulae Volume Formulae