If the sides of a triangle are 56cm, 60 cm and 52cm long, then its area is

a

=

56cm

$b$ $=$ 60 cm

$c =$ 52 cm

$s = \frac{a + b + c}{2} = \frac{56 + 60 + 52}{2} = \frac{168}{2}$ $= 84$ cm

Area $= \sqrt{s \times (s - a) \times (s - b) \times (s - c)}$

$= \sqrt{84 \times (84 - 56) \times (84 - 60) \times (84 - 52)}$

$= \sqrt{84 \times 28 \times 24 \times 32}$

$= \sqrt{12 \times 7 \times 4 \times 7 \times 4 \times 6 \times 16 \times 2}$

$= \sqrt{2 \times 6 \times 7 \times 4 \times 7 \times 4 \times 6 \times 16 \times 2}$

$= 2 \times 6 \times 7 \times 4 \times 4$

$= 1344 {cm}^{2}$

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