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If the sum of an infinite decreasing G.P. is 3 and sum of the cubes of its terms is 108/13, then common ratio is given by

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a
15
b
14
c
13
d
12

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detailed solution

Correct option is C

a1r=3,a31r3=10813 where  |r|<1

27(1r)31r3=10813

12r+r21+r+r2=4131326r+13r2=4+4r+4r29r230r+9=03r210r+3=0.(3r1)(r3)=0r=1/3 [|r|<1]

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