If   W=123321,X=102−102 and  Y=01−25 then  WX+Y is

# If   $W=\left[\begin{array}{ccc}1& 2& 3\\ 3& 2& 1\end{array}\right],X=\left[\begin{array}{cc}1& 0\\ 2& -1\\ 0& 2\end{array}\right]$ and  $Y=\left[\begin{array}{cc}0& 1\\ -2& 5\end{array}\right]$ then  $WX+Y$ is

1. A

$\left[\begin{array}{cc}5& 5\\ 5& 5\end{array}\right]$

2. B

$\left[\begin{array}{cc}0& 1\\ 2& -3\\ -4& 10\end{array}\right]$

3. C

$\left[\begin{array}{cc}2& 5\\ 3& 0\end{array}\right]$

4. D

$\left[\begin{array}{cc}-8& 20\\ -8& 13\end{array}\right]$

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### Solution:

$\begin{array}{l}WX=\left[\begin{array}{ccc}1& 2& 3\\ 3& 2& 1\end{array}\right]×\left[\begin{array}{cc}1& 0\\ 2& -1\\ 0& 2\end{array}\right]=\left[\begin{array}{cc}1\left(1\right)+2\left(2\right)+3\left(0\right)& 1\left(0\right)+2\left(-1\right)+3\left(2\right)\\ 3\left(1\right)+2\left(2\right)+1\left(0\right)& 3\left(0\right)+2\left(-1\right)+1\left(2\right)\end{array}\right]\\ =\left[\begin{array}{cc}5& 4\\ 7& 0\end{array}\right]\\ WX+Y=\left[\begin{array}{cc}5& 4\\ 7& 0\end{array}\right]+\left[\begin{array}{cc}0& 1\\ -2& 5\end{array}\right]=\left[\begin{array}{cc}5& 5\\ 5& 5\end{array}\right]\end{array}$

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