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If x1 and x2 are the arithmetic and harmonic means of the roots of the equation ax2+bx+c=0, the equation whose quadratic roots are x1 and  x2, is

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a
abx2+(b2+ac)x+bc=0
b
2abx2+(b2+4ac)x+2bc=0
c
2abx2+(b2+ac)x+bc=0
d
None of the above 

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detailed solution

Correct option is B

Let α and β be the roots of  ax2+bx+c=0

 x1=α+β2=b2a x2=2αβα+β=2caba=2cb

The required equation is

x2[(b2a)+(2cb)]x+2bc2ab=02abx2+(b2+4ac)x+2bc=0

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