MathematicsIf x=54, y=2, z=43 then

If $x = \sqrt[4]{5}, y = \sqrt{2}, z = \sqrt[3]{4}$ then

A
$x > y > z$
B
$x < y < z$
C
$z > x > y$
D
$y > z > x$

Solution:

x = \sqrt[4]{5}, y = \sqrt{2}, z = \sqrt[3]{4}

Equating the orders

$\Rightarrow \sqrt[4 \times 3]{5^{3}}, \sqrt[2 \times 6]{2^{6}}, \sqrt[3 \times 4]{4^{4}}$

$\Rightarrow \sqrt[12]{125}, \sqrt[12]{64}, \sqrt[12]{256}$

$∴ z > x > y$

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Type of relations_mathematics