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Q.

If π2<θ<π, then 1sinθ1+sinθ+1+sinθ1sinθ is equal to is

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a

-secθ

b

2secθ

c

sec θ

d

2secθ

answer is B.

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Detailed Solution

We have,

1sinθ1+sinθ+1+sinθ1sinθ=1sinθ+1+sinθ1sin2θ=2|cosθ|=2cosθ=2secθ,   π/2<θ<πcosθ<0

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