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Q.

If 2+i3 is a root of the equation  x2+px+q=0, then  (p,q)= 

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a

(4,7)

b

(4,7)

c

(4,7)

d

(4,7)

answer is C.

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Detailed Solution

x2+(2+i3+2i3)x+(2+i3)(2i3)=0

p=(α+β)q=αβ

p=4

q=22(i3)2

=4+3

=7

(p,q)=(4,7)

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