If A=0a+1b−22a−10c−22b−12+c0 is a skew symmetric then a+b+c= - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

Solution:

$A = [\begin{array}{ccc} 0 & a + 1 & b - 2 \\ 2 a - 1 & 0 & c - 2 \\ 2 b - 1 & 2 + c & 0 \end{array}] A^{T} = - A [\begin{array}{ccc} 0 & 2 a - 1 & 2 b - 1 \\ a + 1 & 0 & 2 + c \\ b - 2 & c - 2 & 0 \end{array}] = [\begin{array}{ccc} 0 & - a - 1 & - b + 2 \\ - 2 a + 1 & 0 & - c + 2 \\ - 2 b + 1 & - 2 - c & 0 \end{array}]$
$2 a - 1 = - a - 1 \Rightarrow a = 0 2 b - 1 = - b + 2 \Rightarrow b = 1 c - 2 = - 2 - c \Rightarrow c = 0 a + b + c = 1$

$If A = [\begin{array}{ccc} 0 & a + 1 & b - 2 \\ 2 a - 1 & 0 & c - 2 \\ 2 b - 1 & 2 + c & 0 \end{array}] is a skew symmetric then a + b + c =$

Solution:

Related content