Search for: If a=2sinθ1+cosθ+sinθ, then 1+sinθ−cosθ1+sinθ is equal to If a=2sinθ1+cosθ+sinθ, then 1+sinθ−cosθ1+sinθ is equal to A1aBaC1-aD1+a Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have, a=2sinθ1+cosθ+sinθ⇒ a=2sinθ(1+sinθ−cosθ)(1+cosθ+sinθ)(1+sinθ−cosθ)⇒ a=2sinθ(1+sinθ−cosθ)(1+sinθ)2−cos2θ⇒ a=2sinθ(1+sinθ−cosθ)2sinθ(1+sinθ)=1+sinθ−cosθ1+sinθPost navigationPrevious: An ellipse has OB as a semi-minor axis, F, F’ as its foci and the angle ∠FBF′ is a right angle. Then the eccentricity of the ellipse isNext: The least value of cos2θ−6sinθcosθ+3sin2θ+2, is Related content NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023