MathematicsIf A=cos2π33       sin2π33−sin2π33     cos2π33 then   A2017=

If A=cos2π33       sin2π33sin2π33     cos2π33 then   A2017=

  1. A

    A

  2. B

    A2

  3. C

    A3

  4. D

    A4

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    Solution:

    Let  θ=2π33A=cosθsinθsinθcosθ

    A2017=cos2017θsin2017θsin2017θcos2017θ

    2017θ=20172π33=122π+8π33cos2017θ=cos4θ;

    sin2017θ=sin4θ

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