Search for: If a=tan27θ−tanθ and b=sinθcos3θ+sin3θcos9θ+sin9θcos27θ, thenIf a=tan27θ−tanθ and b=sinθcos3θ+sin3θcos9θ+sin9θcos27θ, thenAa=bBa=2bCb=2aDa+b=2 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have, a=tan27θ−tanθ= a=tan27θ−tan9θ+tan9θ−tan3θ+tan3θ−tanθ⇒ a=sin18θcos27θcos9θ+sin6θcos9θcos3θ+sin2θcos3θcosθ⇒ a=2sin9θcos27θ+sin3θcos9θ+sinθcos3θ⇒a=2bPost navigationPrevious: If the equation sin4θ+cos4θ=a has a real solution thenNext: If cosθa=sinθb, then asec2θ+bcosec2θ is equal toRelated content JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023 JEE Advanced Crash Course – JEE Advanced Crash Course 2023