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If cosθ1=2cosθ2,then tanθ1θ22tanθ1+θ22

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a
13
b
-13
c
1
d
-1

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detailed solution

Correct option is B

tanθ1θ22tanθ1+θ22

=2sinθ1+θ22sinθ1θ222cosθ1+θ22cosθ1θ22

=cosθ2cosθ1cosθ1+cosθ2=13

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