Search for: If cosθa=sinθb, then asec2θ+bcosec2θ is equal toIf cosθa=sinθb, then asec2θ+bcosec2θ is equal toAaBbCabDa+b Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:We have, cosθa=sinθb=cosθa=sinθb=cos2θ+sin2θa2+b2−b=cosθ=aa2+b2 and sinθ=ba2+b2 asec2θ+bcosec2θ=acos2θ+bsin2θ= asec2θ+bcosec2θ=acos2θ−sin2θ+2bsinθcosθ= asec20+bcosec2θ≈aa2−b2a2+b2+2ab2a2+b2=aPost navigationPrevious: If a=tan27θ−tanθ and b=sinθcos3θ+sin3θcos9θ+sin9θcos27θ, thenNext: If in a triangle ABC, sinA:sinC=sin(A−B):sin(B−C) then, a2:b2:c2 are in Related content JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3 JEE Crash Course – JEE Crash Course 2023 NEET Crash Course – NEET Crash Course 2023 JEE Advanced Crash Course – JEE Advanced Crash Course 2023