Search for: MathematicsIf cosx2y3+sinx2y3=k then dydxIf cosx2y3+sinx2y3=k then dydxA-2y3xB-3x2yC-sin(x2y3)+(cosx2y3)2y3xD0 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pmPlease indicate your interest Live ClassesBooksTest SeriesSelf LearningLanguage ---EnglishHindiMarathiTamilTeluguMalayalamAre you a Sri Chaitanya student? NoYesVerify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:The given equation is cosx2y3+sinx2y3=kUse the implicit differentiation, differentiate both sides with respect to x-sinx2y3+cosx2y32xy3+3x2y2dydx=0It implies that 2xy3+3x2y2dydx=02y+3xdydx=0dydx=-2y3x Related content Area of Square Area of Isosceles Triangle Pythagoras Theorem Triangle Formulae Perimeter of Triangle Formula Area Formulae Volume of Cone Formula Matrices and Determinants_mathematics Critical Points Solved Examples Type of relations_mathematics