MathematicsIf cosx2y3+sinx2y3=k then dydx

If cosx2y3+sinx2y3=k then dydx

  1. A

    -2y3x

  2. B

    -3x2y

  3. C

    -sin(x2y3)+(cosx2y3)2y3x

  4. D

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    Solution:

    The given equation is cosx2y3+sinx2y3=k

    Use the implicit differentiation, differentiate both sides with respect to x

    -sinx2y3+cosx2y32xy3+3x2y2dydx=0

    It implies that 

    2xy3+3x2y2dydx=02y+3xdydx=0dydx=-2y3x

     

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