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If cosx+cosy+cosα=0 and sinx+siny+sinα=0 then cotx+y2 is equal to

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a
sin α
b
cos α
c
cot α
d
sinx+y2

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detailed solution

Correct option is C

Given equations may be written as

cosx+cosy=cosα and  sinx+siny=sinα 2cosx+y2cosxy2=cosα----i and  2sinx+y2cosxy2=sinα----ii

From Eqs. (i) and (ii), we get

2cosx+y2cosxy22sinx+y2cosxy2=cosαsinα cotx+y2=cotα

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