If ∫f(x)dx=f(x)+C, then ∫{f(x)}2dx is

If f(x)dx=f(x)+C, then {f(x)}2dx is

  1. A

    {f(x)}2+C

  2. B

    13{f(x)}3+C

  3. C

    f(x)+C

  4. D

    12{f(x)}2+C

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    Solution:

    Given,

    f(x)dx=f(x)+Cf(x)=f(x)f(x)2dx=f(x)f(x)dx=12{f(x)}2+C

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