If tan⁡θtan⁡π3+θtan⁡−π3+θ=ktan⁡3θ, then the value of k, is 

If tanθtanπ3+θtanπ3+θ=ktan3θ, then the value of k, is 

  1. A

    1

  2. B

    1/3

  3. C

    3

  4. D

    -1

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    Solution:

    We have,

      tanθtanπ3+θtanπ3+θ=ktan3θ

     tanθtanθ+313tanθtanθ31+3tanθ=ktan3θ tan3θ3tanθ13tan2θ=ktan3θ tan3θ=ktan3θk=1

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