MathematicsIf x = 2at1+t2, y=b1-t21+t2, then  dydx

If x = 2at1+t2, y=b1-t21+t2, then  dydx

  1. A

    -xy

  2. B

    yx

  3. C

    -b2xa2y

  4. D

    b2xa2y

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    Solution:

    Given x = 2at1+t2, y=b1-t21+t2,

    Differentiate both x and y with respect to t

    dxdt=ddt2at1+t2 =2a1+t21-t2t1+t22 =2a1+t2-2t21+t22 =2a1-t21+t22

    dydt=ddt b1-t21+t2 =b1+t2-2t-1-t22t1+t22 =-2bt1+t2+1-t21+t22 =-4bt1+t22

    Use the concept of parametric differentiation 

    dydx=dydt·dtdx =-4bt1+t22·1+t222a1-t2 =2bta1-t2 =bxaayb =b2xa2y

     

     

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