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Q.

If x = 2at1+t2, y=b1-t21+t2, then  dydx

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a

yx

b

-b2xa2y

c

-xy

d

b2xa2y

answer is C.

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Detailed Solution

Given x = 2at1+t2, y=b1-t21+t2,

Differentiate both x and y with respect to t

dxdt=ddt2at1+t2 =2a1+t21-t2t1+t22 =2a1+t2-2t21+t22 =2a1-t21+t22

dydt=ddt b1-t21+t2 =b1+t2-2t-1-t22t1+t22 =-2bt1+t2+1-t21+t22 =-4bt1+t22

Use the concept of parametric differentiation 

dydx=dydt·dtdx =-4bt1+t22·1+t222a1-t2 =-2bta1-t2 =-bxaayb =-b2xa2y

 

 

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If x = 2at1+t2, y=b1-t21+t2, then  dydx