If xcos⁡θ=ycos⁡θ+2π3=zcos⁡θ+4π3,then the value of  1x+1y+1z is equal to 

If xcosθ=ycosθ+2π3=zcosθ+4π3,then the value of  1x+1y+1z is equal to 

  1. A

    1

  2. B

    2

  3. C

    0

  4. D

    3 cos θ

    Register to Get Free Mock Test and Study Material

    +91

    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    We have, xcosθ=ycosθ+2π3=zcosθ+4π3=k 

     cosθ=kx, cosθ+2π3=ky and cosθ+4π3=kz kx+ky+kz=cosθ+cosθ+2π3+cosθ+4π3 =cosθcosπ3θcosπ3+θ =cosθ2cosπ3cosθ=0 1x+1y+1z=0 

    Chat on WhatsApp Call Infinity Learn

      Register to Get Free Mock Test and Study Material

      +91

      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.