If y2=4ax, then dydx is

ddx(y2)=ddx(4ax)⇒2y.dydx=4addx(x)⇒2ydydx=4a(1)⇒dydx=4a2ydydx=2ay=2a4ax=ax

If y2=4ax, then dydx is

ddx(y2)=ddx(4ax)⇒2y.dydx=4addx(x)⇒2ydydx=4a(1)⇒dydx=4a2ydydx=2ay=2a4ax=ax

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

If $y^{2} = 4 a x$ , then $\frac{d y}{d x}$ is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$\sqrt{\frac{a}{x}}$

$\sqrt{a x}$

$\sqrt{a + x}$

$\sqrt{a - x}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{l} \frac{d}{d x} (y^{2}) = \frac{d}{d x} (4 a x) \Rightarrow 2 y . \frac{d y}{d x} = 4 a \frac{d}{d x} (x) \\ \Rightarrow 2 y \frac{d y}{d x} = 4 a (1) \Rightarrow \frac{d y}{d x} = \frac{4 a}{2 y} \\ \frac{d y}{d x} = \frac{2 a}{y} = \frac{2 a}{\sqrt{4 a x}} = \sqrt{\frac{a}{x}} \end{array}$