Search for: In a triangle ABC, 2ac sin12(A-B+C)= In a triangle ABC, 2ac sin12(A-B+C)= Aa2+b2-c2 Bc2+a2-b2Cb2-c2-a2Dc2-a2-b2 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:12(A-B+C) =12(π-B-B) =π2-B∴ 2ac sin12(A-B+C)=2ac sinπ2-B= 2ac cos B=a2+c2-b2 (by cosine rule)Post navigationPrevious: 2 sin2θ + 4 cos(θ + α) sinα sinθ + cos 2(θ + α) =Next: If x and y are positive integers such that xy+x+y = 71, x2y +xy2 =880, then x 2+y2 is equal toRelated content JEE Main 2023 Session 2 Registration to begin today JEE Main 2023 Result: Session 1 NEET 2024 JEE Advanced 2023 NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria