Search for: In a triangle ABC, if tanA : tanB : tanC =1 : 2 : 3, then a2 : b2 : c2 =In a triangle ABC, if tanA : tanB : tanC =1 : 2 : 3, then a2 : b2 : c2 =A5 : 8 :9B5 : 8 : 12C3 : 5 : 8D5 : 8 : 10 Register to Get Free Mock Test and Study Material +91 Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:tanA1=tanB2=tanC3=k (say)∈ tanA=πtanA ⇒6k=6 k3⇒k=1∴ tanA=1, tanB=2, tanC=3⇒ cotA=1, cotB=12, cotC=13, ⇒cosec2A=2,cosec2B=54,cosec2C=109⇒sin2A=12,sin2B=45,sin2C=910∴a2:b2:c2=sin2A:sin2B:sin2C =12:45:910=5:8:9.Post navigationPrevious: The number of roots of the equation cos3x+cos2x=sin3×2+sinx2 in [0,2π] isNext: The sum of the roots of the equation sin2θ-cosθ=14 in [0,2π] isRelated content NEET 2024 JEE Advanced 2023 NEET Rank Assurance Program | NEET Crash Course 2023 JEE Main 2023 Question Papers with Solutions JEE Main 2024 Syllabus Best Books for JEE Main 2024 JEE Advanced 2024: Exam date, Syllabus, Eligibility Criteria JEE Main 2024: Exam dates, Syllabus, Eligibility Criteria JEE 2024: Exam Date, Syllabus, Eligibility Criteria NCERT Solutions For Class 6 Maths Data Handling Exercise 9.3