In a triangle ABC, if tanA : tanB : tanC =1 : 2 : 3, then a2 : b2  : c2 =

In a triangle ABC, if tanA : tanB : tanC =1 : 2 : 3, then a2 : b2  : c2 =

  1. A

    5 : 8 :9

  2. B

    5 : 8 : 12

  3. C

    3 : 5 : 8

  4. D

    5 : 8 : 10

    Register to Get Free Mock Test and Study Material

    +91

    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    tanA1=tanB2=tanC3=k (say)

       tanA=πtanA 6k=6 k3

    k=1

     tanA=1, tanB=2, tanC=3

     cotA=1, cotB=12, cotC=13,

     cosec2A=2,cosec2B=54,cosec2C=109sin2A=12,sin2B=45,sin2C=910a2:b2:c2=sin2A:sin2B:sin2C =12:45:910=5:8:9.

    Chat on WhatsApp Call Infinity Learn

      Register to Get Free Mock Test and Study Material

      +91

      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.